Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 12:10Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
438K
4y² + 7y + 7 = 0
∇²t = 0
det| 12 6 ; 0 13 | = 156
448K
∫₀^∞ e^(-y²) dy = √π / 2
22K
6β² + 2β + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
406K
2φ² + 2φ + 5 = 0
det| 9 4 ; 1 10 | = 86
359K