Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z
∇²n = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
263K
9r² + 4r + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
108K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
11γ² + 3γ + 6 = 0
det| 7 2 ; 7 8 | = 42
413K
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
∑_{k=1}^{n} k = n(n+1)/2
58K