Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-21 10:00Z
6y² + 3y + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
262K
ΔS ≥ 0
det| 4 5 ; 4 5 | = 0
det| 9 4 ; 1 10 | = 86
26K
iħ ∂ψ/∂t = Ĥψ
∂t/∂α = 6t
∑_{k=1}^{n} k = n(n+1)/2
163K
ΔS ≥ 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-φ²) dφ = √π / 2
9t² + 6t + 4 = 0