Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 20:58Z
det| 6 5 ; 4 7 | = 22
\binom{n}{k} = \frac{n!}{k!(n-k)!}
438K
∇²φ = 0
\frac{9}{2} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
448K
F = ma
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
80K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
359K
∇²γ = 0