Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:21Z
∇²n = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
273K
9r² + 4r + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
108K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
333K
det| 9 4 ; 1 10 | = 86
160K
\lim_{t\to 0} \frac{\sin t}{t} = 1
439K
∫₀^∞ e^(-x²) dx = √π / 2
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