Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-21 09:59Z

∫₀^∞ e^(-z²) dz = √π / 2

d/dt [t^3] = 3t^2

195K

det| 9 4 ; 1 10 | = 86

262K

10ω² + 8ω + 0 = 0

det| 11 4 ; 5 12 | = 112

∫₀^∞ e^(-θ²) dθ = √π / 2

244K

2H₂ + O₂ → 2H₂O

det| 4 8 ; 3 5 | = -4

231K

∑_{k=1}^{n} k = n(n+1)/2

26K

9r² + 6r + 7 = 0

6ω² + 4ω + 4 = 0

209K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

331K

12θ² + 8θ + 7 = 0

∑_{k=1}^{n} k = n(n+1)/2

163K

10r² + 5r + 3 = 0

12γ² + 9γ + 7 = 0

5φ² + 3φ + 2 = 0