Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 19:21Z
\frac{11}{4} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
451K
∫₀^∞ e^(-α²) dα = √π / 2
264K
d/dx [x^3] = 3x^2
det| 7 8 ; 4 8 | = 24
297K
\frac{12}{8} \sum_{i=1}^{n} i^{2}
det| 5 9 ; 7 6 | = -33
48K
F = ma
det| 7 4 ; 4 8 | = 40
299K
AgNO₃ + NaCl → AgCl↓ + NaNO₃