Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:05Z

10y² + 2y + 6 = 0

N₂ + 3H₂ ⇌ 2NH₃

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-t²) dt = √π / 2

e^{i\pi} + 1 = 0

186K

det| 10 2 ; 3 11 | = 104

411K

e^{i\pi} + 1 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

8ψ² + 7ψ + 0 = 0

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 4 8 ; 3 5 | = -4

459K

det| 7 8 ; 4 8 | = 24

406K

λ = h/p

d/dt [t^3] = 3t^2

181K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

80K

∇ × E = −∂B/∂t

359K

PV = nRT

455K