Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:18Z

10γ² + 4γ + 3 = 0

10β² + 4β + 1 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

438K

d/dβ [β^11] = 11β^10

\frac{8}{7} \sum_{i=1}^{n} i^{2}

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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3x² + 4x + 6 = 0

∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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CaCO₃ → CaO + CO₂

N₂ + 3H₂ ⇌ 2NH₃

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∇²β = 0

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6r² + 3r + 1 = 0

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8γ² + 1γ + 1 = 0

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det| 7 4 ; 4 8 | = 40

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∂y/∂n = 5y

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