Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:44Z

10γ² + 4γ + 3 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

460K

6ω² + 4ω + 4 = 0

438K

d/dβ [β^11] = 11β^10

ΔS ≥ 0

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

3x² + 4x + 6 = 0

det| 7 4 ; 4 8 | = 40

448K

∇²r = 0

22K

CaCO₃ → CaO + CO₂

N₂ + 3H₂ ⇌ 2NH₃

459K

∫₀^∞ e^(-t²) dt = √π / 2

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

181K

9ψ² + 7ψ + 3 = 0

80K

\lim_{t\to 0} \frac{\sin t}{t} = 1

359K