Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:18Z
∇²n = 0
∫₀^∞ e^(-α²) dα = √π / 2
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9r² + 4r + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
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11γ² + 3γ + 6 = 0
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
det| 11 4 ; 5 12 | = 112
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∑_{k=1}^{n} k = n(n+1)/2
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∫₀^∞ e^(-θ²) dθ = √π / 2
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