Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 15:55Z
11n² + 5n + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K
∫₀^∞ e^(-x²) dx = √π / 2
det| 2 3 ; 5 3 | = -9
186K
4φ² + 6φ + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
448K
det| 7 4 ; 4 8 | = 40
22K
det| 10 2 ; 3 11 | = 104
459K
det| 4 8 ; 3 5 | = -4
406K