Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-21 09:59Z
∫₀^∞ e^(-z²) dz = √π / 2
10ω² + 8ω + 0 = 0
∫₀^∞ e^(-t²) dt = √π / 2
2K
2H₂ + O₂ → 2H₂O
det| 2 8 ; 7 3 | = -50
26K
9r² + 6r + 7 = 0
det| 3 6 ; 0 4 | = 12
331K
12θ² + 8θ + 7 = 0
det| 3 7 ; 2 4 | = -2
163K
12γ² + 9γ + 7 = 0
5φ² + 3φ + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂