Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:56Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

iħ ∂ψ/∂t = Ĥψ

438K

∫₀^∞ e^(-x²) dx = √π / 2

8θ² + 8θ + 6 = 0

186K

iħ ∂ψ/∂t = Ĥψ

411K

4φ² + 6φ + 2 = 0

det| 7 6 ; 1 8 | = 50

448K

det| 9 4 ; 1 10 | = 86

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

F = G m₁m₂ / r²

459K

∫₀^∞ e^(-α²) dα = √π / 2

406K

∇²ω = 0

d/dα [α^3] = 3α^2

d/dr [r^2] = 2r^1

ΔS ≥ 0

8β² + 5β + 0 = 0