Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:36Z

N₂ + 3H₂ ⇌ 2NH₃

d/dt [t^3] = 3t^2

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∇ × E = −∂B/∂t

118K

9ψ² + 4ψ + 2 = 0

N₂ + 3H₂ ⇌ 2NH₃

43K

\frac{12}{6} \sum_{i=1}^{n} i^{2}

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d/dβ [β^6] = 6β^5

\lim_{t\to 0} \frac{\sin t}{t} = 1

424K

∑_{k=1}^{n} k = n(n+1)/2

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det| 6 1 ; 4 7 | = 38

∂y/∂n = 5y

41K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

298K

\frac{6}{5} \sum_{i=1}^{n} i^{2}

8ψ² + 7ψ + 0 = 0

447K

5ψ² + 8ψ + 3 = 0

11y² + 2y + 6 = 0

det| 10 3 ; 1 11 | = 107