Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 20:37Z
det| 6 5 ; 4 7 | = 22
∑_{k=1}^{n} k = n(n+1)/2
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∇²φ = 0
∑_{k=1}^{n} k = n(n+1)/2
411K
\frac{9}{2} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
448K
F = ma
det| 7 9 ; 1 8 | = 47
406K
∑_{k=1}^{n} k = n(n+1)/2
181K
∑_{k=1}^{n} k = n(n+1)/2
80K