Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:39Z

3γ² + 8γ + 4 = 0

N₂ + 3H₂ ⇌ 2NH₃

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7r² + 8r + 5 = 0

438K

PV = nRT

∑_{k=1}^{n} k = n(n+1)/2

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\frac{4}{6} \sum_{i=1}^{n} i^{2}

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det| 1 9 ; 5 2 | = -43

N₂ + 3H₂ ⇌ 2NH₃

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8ψ² + 7ψ + 0 = 0

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ω = 2πf

iħ ∂ψ/∂t = Ĥψ

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8γ² + 1γ + 1 = 0

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∂n/∂ψ = 6n

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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∑_{k=1}^{n} k = n(n+1)/2

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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