Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:34Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

∫₀^∞ e^(-t²) dt = √π / 2

186K

d/dφ [φ^1] = 1φ^0

411K

4φ² + 6φ + 2 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

d/dt [t^3] = 3t^2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 9 4 ; 1 10 | = 86

459K

∂ψ/∂β = 3ψ

406K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

181K

2H₂ + O₂ → 2H₂O

80K