Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:33Z

∇²t = 0

∇ × E = −∂B/∂t

460K

2H₂ + O₂ → 2H₂O

438K

det| 6 4 ; 3 7 | = 30

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

186K

det| 11 9 ; 0 12 | = 132

411K

ΔS ≥ 0

∑_{k=1}^{n} k = n(n+1)/2

448K

e^{i\pi} + 1 = 0

22K

8ψ² + 7ψ + 0 = 0

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

d/dt [t^3] = 3t^2

181K

det| 10 2 ; 3 11 | = 104

80K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

359K

ω = 2πf

455K