Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:21Z

11n² + 5n + 4 = 0

N₂ + 3H₂ ⇌ 2NH₃

460K

\lim_{β\to 0} \frac{\sin β}{β} = 1

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 7 4 ; 4 8 | = 40

186K

CH₄ + 2O₂ → CO₂ + 2H₂O

411K

4φ² + 6φ + 2 = 0

∇ × E = −∂B/∂t

448K

2H₂ + O₂ → 2H₂O

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

CH₄ + 2O₂ → CO₂ + 2H₂O

459K

F = G m₁m₂ / r²

406K