Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:38Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

d/dt [t^3] = 3t^2

438K

∫₀^∞ e^(-x²) dx = √π / 2

∫₀^∞ e^(-θ²) dθ = √π / 2

186K

∫₀^∞ e^(-ω²) dω = √π / 2

411K

4φ² + 6φ + 2 = 0

8x² + 2x + 7 = 0

448K

e^{i\pi} + 1 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

4γ² + 1γ + 7 = 0

459K

9θ² + 7θ + 4 = 0

406K

∇²ω = 0

∇ × E = −∂B/∂t

181K

8ψ² + 7ψ + 0 = 0

80K

\lim_{β\to 0} \frac{\sin β}{β} = 1

359K

∇ × E = −∂B/∂t

455K