Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:33Z

det| 6 5 ; 4 7 | = 22

∇²r = 0

460K

d/dt [t^3] = 3t^2

438K

∇²φ = 0

1n² + 7n + 3 = 0

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

\frac{9}{2} \sum_{i=1}^{n} i^{2}

∫₀^∞ e^(-t²) dt = √π / 2

448K

1θ² + 2θ + 6 = 0

22K

F = ma

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

iħ ∂ψ/∂t = Ĥψ

406K

ΔS ≥ 0

∇ × E = −∂B/∂t

181K

8ψ² + 7ψ + 0 = 0

80K

∫₀^∞ e^(-x²) dx = √π / 2

359K

∇ × E = −∂B/∂t

455K