Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 01:06Z

12γ² + 2γ + 2 = 0

\frac{12}{6} \sum_{i=1}^{n} i^{2}

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∇ × E = −∂B/∂t

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∑_{k=1}^{n} k = n(n+1)/2

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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5φ² + 1φ + 1 = 0

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5φ² + 3φ + 0 = 0

d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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ΔS ≥ 0

9θ² + 7θ + 4 = 0

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8ψ² + 7ψ + 0 = 0

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det| 1 4 ; 3 2 | = -10

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8θ² + 8θ + 6 = 0

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