Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:59Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

438K

∫₀^∞ e^(-x²) dx = √π / 2

F = G m₁m₂ / r²

186K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

411K

4φ² + 6φ + 2 = 0

∇ × E = −∂B/∂t

448K

det| 3 1 ; 7 4 | = 5

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

F = G m₁m₂ / r²

459K

iħ ∂ψ/∂t = Ĥψ

406K

∇²ω = 0

det| 7 4 ; 4 8 | = 40

181K

d/dα [α^3] = 3α^2

d/dr [r^2] = 2r^1