Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:51Z

11n² + 5n + 4 = 0

det| 9 4 ; 1 10 | = 86

460K

2H₂ + O₂ → 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 3 7 ; 2 4 | = -2

186K

PV = nRT

411K

4φ² + 6φ + 2 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

\lim_{t\to 0} \frac{\sin t}{t} = 1

22K

∑_{k=1}^{n} k = n(n+1)/2

459K

det| 3 6 ; 0 4 | = 12

406K

d/dt [t^3] = 3t^2

181K

F = ma

80K

E = mc²

359K

5φ² + 1φ + 1 = 0

455K