Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:34Z

∇²t = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

460K

CH₄ + 2O₂ → CO₂ + 2H₂O

438K

det| 6 4 ; 3 7 | = 30

∫₀^∞ e^(-ω²) dω = √π / 2

186K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

411K

ΔS ≥ 0

∑_{k=1}^{n} k = n(n+1)/2

448K

d/dt [t^3] = 3t^2

22K

1z² + 3z + 2 = 0

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

459K

7γ² + 8γ + 3 = 0

406K

7t² + 3t + 1 = 0

iħ ∂ψ/∂t = Ĥψ

181K

det| 10 7 ; 3 11 | = 89

80K

det| 9 4 ; 1 10 | = 86

359K