Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:24Z

∑_{k=1}^{n} k = n(n+1)/2

d/dt [t^3] = 3t^2

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∑_{k=1}^{n} k = n(n+1)/2

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det| 8 9 ; 3 9 | = 45

∑_{k=1}^{n} k = n(n+1)/2

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6t² + 6t + 4 = 0

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

9θ² + 7θ + 4 = 0

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det| 5 2 ; 3 6 | = 24

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det| 2 3 ; 3 3 | = -3

e^{i\pi} + 1 = 0

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det| 9 4 ; 1 10 | = 86

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