Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:21Z

3γ² + 8γ + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

∇²β = 0

438K

PV = nRT

8ψ² + 7ψ + 0 = 0

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∇ × E = −∂B/∂t

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det| 1 9 ; 5 2 | = -43

\frac{2}{2} \sum_{i=1}^{n} i^{2}

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d/dt [t^3] = 3t^2

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ω = 2πf

\lim_{t\to 0} \frac{\sin t}{t} = 1

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∑_{k=1}^{n} k = n(n+1)/2

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10t² + 9t + 5 = 0

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