Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:50Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∇ × E = −∂B/∂t

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 11 4 ; 5 12 | = 112

186K

CH₄ + 2O₂ → CO₂ + 2H₂O

411K

4φ² + 6φ + 2 = 0

8ψ² + 7ψ + 0 = 0

448K

d/dt [t^3] = 3t^2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

10ω² + 7ω + 4 = 0

406K

∇²ω = 0

d/dα [α^3] = 3α^2

d/dr [r^2] = 2r^1