Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 20:38Z
det| 6 5 ; 4 7 | = 22
∑_{k=1}^{n} k = n(n+1)/2
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∇²φ = 0
det| 4 2 ; 6 5 | = 8
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\frac{9}{2} \sum_{i=1}^{n} i^{2}
det| 9 4 ; 1 10 | = 86
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∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
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