Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 19:47Z

CH₄ + 2O₂ → CO₂ + 2H₂O

6ω² + 4ω + 4 = 0

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

det| 1 1 ; 4 2 | = -2

e^{i\pi} + 1 = 0

186K

CH₄ + 2O₂ → CO₂ + 2H₂O

411K

CaCO₃ → CaO + CO₂

∇²t = 0

448K

8ψ² + 7ψ + 0 = 0

22K

det| 8 4 ; 2 9 | = 64

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

∇²n = 0

406K

4n² + 8n + 6 = 0

d/dt [t^3] = 3t^2

181K

10ω² + 7ω + 4 = 0

80K

∇ × E = −∂B/∂t

359K

∑_{k=1}^{n} k = n(n+1)/2

455K