Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:17Z

∇²n = 0

d/dt [t^3] = 3t^2

273K

∫₀^∞ e^(-t²) dt = √π / 2

263K

9r² + 4r + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

139K

∇²ω = 0

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

PV = nRT

333K

\frac{4}{9} \sum_{i=1}^{n} i^{2}

160K

11γ² + 3γ + 6 = 0

∂x/∂ψ = 6x

439K

6r² + 3r + 1 = 0

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

∇ × E = −∂B/∂t

297K

8ψ² + 7ψ + 0 = 0

128K

iħ ∂ψ/∂t = Ĥψ

404K