Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 20:24Z
det| 10 4 ; 6 11 | = 86
∑_{k=1}^{n} k = n(n+1)/2
263K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
11r² + 8r + 6 = 0
det| 2 3 ; 5 3 | = -9
333K
det| 5 6 ; 2 6 | = 18
160K
∇²ω = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
439K
∑_{k=1}^{n} k = n(n+1)/2
413K
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
9r² + 9r + 2 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}