Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 11:32Z
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
det| 6 4 ; 3 7 | = 30
∫₀^∞ e^(-t²) dt = √π / 2
186K
ΔS ≥ 0
∫₀^∞ e^(-θ²) dθ = √π / 2
22K
1z² + 3z + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
459K
det| 9 4 ; 1 10 | = 86
406K
7t² + 3t + 1 = 0
det| 11 5 ; 2 12 | = 122