Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 16:11Z
∂ψ/∂φ = 6ψ
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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11ψ² + 2ψ + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
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λ = h/p
\frac{9}{7} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\frac{2}{8} \sum_{i=1}^{n} i^{2}
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
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\frac{10}{3} \sum_{i=1}^{n} i^{2}
det| 9 4 ; 1 10 | = 86
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