Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:58Z

det| 6 5 ; 4 7 | = 22

det| 3 1 ; 7 4 | = 5

460K

∇ × E = −∂B/∂t

438K

∇²φ = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

186K

∇²t = 0

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\frac{9}{2} \sum_{i=1}^{n} i^{2}

d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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F = ma

∑_{k=1}^{n} k = n(n+1)/2

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8ψ² + 7ψ + 0 = 0

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∇²θ = 0

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10ω² + 7ω + 4 = 0

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