Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:34Z

11n² + 5n + 4 = 0

det| 2 3 ; 5 3 | = -9

460K

∇ × E = −∂B/∂t

438K

∫₀^∞ e^(-x²) dx = √π / 2

λ = h/p

186K

N₂ + 3H₂ ⇌ 2NH₃

411K

4φ² + 6φ + 2 = 0

iħ ∂ψ/∂t = Ĥψ

448K

CH₄ + 2O₂ → CO₂ + 2H₂O

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∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

det| 7 4 ; 4 8 | = 40

181K

12y² + 5y + 7 = 0

80K

CH₄ + 2O₂ → CO₂ + 2H₂O

359K

F = G m₁m₂ / r²

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