Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:54Z

11n² + 5n + 4 = 0

F = ma

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

11φ² + 4φ + 0 = 0

186K

6ω² + 4ω + 4 = 0

411K

4φ² + 6φ + 2 = 0

iħ ∂ψ/∂t = Ĥψ

448K

d/dt [t^3] = 3t^2

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∫₀^∞ e^(-φ²) dφ = √π / 2

det| 9 4 ; 1 10 | = 86

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∂ψ/∂β = 3ψ

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

181K

\lim_{r\to 0} \frac{\sin r}{r} = 1

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