Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:39Z

N₂ + 3H₂ ⇌ 2NH₃

12θ² + 2θ + 6 = 0

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12n² + 2n + 2 = 0

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9ψ² + 4ψ + 2 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

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∑_{k=1}^{n} k = n(n+1)/2

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d/dβ [β^6] = 6β^5

PV = nRT

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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∇ × E = −∂B/∂t

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iħ ∂ψ/∂t = Ĥψ

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\frac{2}{2} \sum_{i=1}^{n} i^{2}

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N₂ + 3H₂ ⇌ 2NH₃

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det| 7 4 ; 4 8 | = 40

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N₂ + 3H₂ ⇌ 2NH₃

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