Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:57Z

11n² + 5n + 4 = 0

N₂ + 3H₂ ⇌ 2NH₃

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

e^{i\pi} + 1 = 0

186K

∇²β = 0

411K

4φ² + 6φ + 2 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

F = G m₁m₂ / r²

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

∇²γ = 0

459K

∂x/∂ψ = 6x

406K

∇²ω = 0

det| 7 4 ; 4 8 | = 40

181K

det| 7 9 ; 1 8 | = 47

80K

∇ × E = −∂B/∂t

359K

1θ² + 2θ + 6 = 0

455K