Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:49Z

11t² + 8t + 0 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

∫₀^∞ e^(-z²) dz = √π / 2

438K

∂ω/∂β = 7ω

det| 7 4 ; 4 8 | = 40

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F = G m₁m₂ / r²

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det| 3 3 ; 7 4 | = -9

\frac{12}{6} \sum_{i=1}^{n} i^{2}

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det| 2 3 ; 5 3 | = -9

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PV = nRT

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇ × E = −∂B/∂t

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N₂ + 3H₂ ⇌ 2NH₃

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∇²θ = 0

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11t² + 9t + 7 = 0

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e^{i\pi} + 1 = 0

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