Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 21:35Z

E = mc²

e^{i\pi} + 1 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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e^{i\pi} + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

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E = mc²

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iħ ∂ψ/∂t = Ĥψ

∑_{k=1}^{n} k = n(n+1)/2

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det| 7 4 ; 4 8 | = 40

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det| 7 4 ; 3 8 | = 44

5z² + 8z + 3 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 12 7 ; 1 13 | = 149

N₂ + 3H₂ ⇌ 2NH₃

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10γ² + 8γ + 7 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

∑_{k=1}^{n} k = n(n+1)/2

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10ψ² + 6ψ + 7 = 0