Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:34Z

∇²t = 0

E = mc²

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det| 9 4 ; 1 10 | = 86

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det| 6 4 ; 3 7 | = 30

∑_{k=1}^{n} k = n(n+1)/2

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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ΔS ≥ 0

8x² + 2x + 7 = 0

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\frac{2}{2} \sum_{i=1}^{n} i^{2}

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1z² + 3z + 2 = 0

F = G m₁m₂ / r²

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\lim_{r\to 0} \frac{\sin r}{r} = 1

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iħ ∂ψ/∂t = Ĥψ

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