Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:34Z

3γ² + 8γ + 4 = 0

∇ × E = −∂B/∂t

460K

∇²ω = 0

438K

PV = nRT

d/dφ [φ^1] = 1φ^0

186K

∇ × E = −∂B/∂t

411K

det| 1 9 ; 5 2 | = -43

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

N₂ + 3H₂ ⇌ 2NH₃

22K

ω = 2πf

∑_{k=1}^{n} k = n(n+1)/2

459K

F = G m₁m₂ / r²

406K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K

det| 7 4 ; 4 8 | = 40

80K

det| 8 9 ; 4 9 | = 36

359K