Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:21Z

∑_{k=1}^{n} k = n(n+1)/2

CH₄ + 2O₂ → CO₂ + 2H₂O

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6ω² + 4ω + 4 = 0

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det| 8 9 ; 3 9 | = 45

8ψ² + 7ψ + 0 = 0

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det| 10 7 ; 3 11 | = 89

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

N₂ + 3H₂ ⇌ 2NH₃

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iħ ∂ψ/∂t = Ĥψ

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2n² + 4n + 0 = 0

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10γ² + 8γ + 7 = 0

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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