Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:53Z

10γ² + 4γ + 3 = 0

det| 11 5 ; 0 12 | = 132

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∑_{k=1}^{n} k = n(n+1)/2

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d/dβ [β^11] = 11β^10

det| 7 4 ; 4 8 | = 40

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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3x² + 4x + 6 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

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N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

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N₂ + 3H₂ ⇌ 2NH₃

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