Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 22:11Z
3n² + 7n + 7 = 0
\lim_{r\to 0} \frac{\sin r}{r} = 1
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∫₀^∞ e^(-ω²) dω = √π / 2
det| 9 4 ; 1 10 | = 86
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\frac{10}{6} \sum_{i=1}^{n} i^{2}
det| 11 4 ; 5 12 | = 112
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d/dr [r^12] = 12r^11
\lim_{β\to 0} \frac{\sin β}{β} = 1
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\frac{4}{6} \sum_{i=1}^{n} i^{2}
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∑_{k=1}^{n} k = n(n+1)/2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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