Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:15Z

∇²n = 0

8ψ² + 7ψ + 0 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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9r² + 4r + 1 = 0

iħ ∂ψ/∂t = Ĥψ

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

λ = h/p

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N₂ + 3H₂ ⇌ 2NH₃

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det| 5 6 ; 2 6 | = 18

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∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

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