Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 21:41Z
10y² + 2y + 6 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
460K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
438K
∫₀^∞ e^(-t²) dt = √π / 2
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
448K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
459K
det| 9 4 ; 1 10 | = 86
406K
λ = h/p
det| 7 8 ; 4 8 | = 24
181K
d/dγ [γ^3] = 3γ^2
det| 3 1 ; 7 4 | = 5
359K
det| 11 5 ; 0 12 | = 132
455K
det| 10 7 ; 2 11 | = 96