Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 18:12Z

e^{i\pi} + 1 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 7 4 ; 4 8 | = 40

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λ = h/p

N₂ + 3H₂ ⇌ 2NH₃

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ω = 2πf

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det| 6 7 ; 7 7 | = -7

∇²n = 0

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∑_{k=1}^{n} k = n(n+1)/2

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∇²ψ = 0

∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-x²) dx = √π / 2

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∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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E = mc²

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